In the fairy tale, how many days did Rumpelstiltskin give the queen to guess his name?

"Rumpelstiltskin" is a fairy tale popularly associated with Germany. The tale was one collected by the Brothers Grimm in the 1812 edition of "Children's and Household Tales". The story of "Rumpelstiltskin" is as follows:

A boastful miller pretends that his daughter can spin straw into gold, and so she is locked into a room full of straw and ordered to spin it into gold by the next morning. A little man appears and offers his help in exchange for her necklace. The greedy treasurer makes her spin twice more until the only thing she has left to give the little man is the promise of her first-born child.

The delighted king marries the miller's daughter, but when their child is a year old, the little man returns to claim his payment. Because he likes the miller's daughter (who is now the queen), he allows her to save her child if she can guess his name in three days. At first she failed, but before the final night, her parents followed Rumpelstiltskin to the woods and they overheard him singing. While he was singing and hopping around the fire, they discovered his name as Rumpelstiltskin. When the dwarf came to the queen on the third day and she revealed his name, Rumpelstiltskin lost his bargain. He was so angry and stamped the floor so hard and vanished in a puff of smoke. The miller learnt his lesson and he promised her that he would never boast again.